derivative f(x)= 4/(3x^2)+1/(x^{2.1)}

Lösung

ableitung von

f (x) = \frac{4}{3 x ^{2}} + \frac{1}{x ^{2.1}}

- \frac{2.66666 \dots}{x ^{3}} - \frac{2.1}{x ^{3.1}}

Schritte zur Lösung

\frac{d}{d x} (\frac{4}{3 x ^{2}} + \frac{1}{x ^{2.1}})

Vereinfache

\frac{4}{3 x ^{2}} + \frac{1}{x ^{2.1}} : \frac{1.33333 \dots}{x ^{2}} + \frac{1}{x ^{2.1}}

= \frac{d}{d x} (\frac{1.33333 \dots}{x ^{2}} + \frac{1}{x ^{2.1}})

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (\frac{1.33333 \dots}{x ^{2}}) + \frac{d}{d x} (\frac{1}{x ^{2.1}})

\frac{d}{d x} (\frac{1.33333 \dots}{x ^{2}}) = - \frac{2.66666 \dots}{x ^{3}}

\frac{d}{d x} (\frac{1}{x ^{2.1}}) = - \frac{2.1}{x ^{3.1}}

= - \frac{2.66666 \dots}{x ^{3}} - \frac{2.1}{x ^{3.1}}

\int \frac{( 8 + x + x ^{2} )}{x} d x

x \to 4 - lim (\frac{6 x}{x - 4})

f (x) = 3 sin^{2} (x)

2 y^{^{''}} + y^{^{'}} - 2 y = 0

x \to 5 lim (cos (x))