(\partial)/(\partial x)(ze^{x+y}-xy)

Lösung

\frac{\partial}{\partial x} (z e^{x + y} - x y)

z e^{x + y} - y

Schritte zur Lösung

\frac{\partial}{\partial x} (z e^{x + y} - x y)

Behandle

z, y

als Konstanten

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (z e^{x + y}) - \frac{\partial}{\partial x} (x y)

\frac{\partial}{\partial x} (z e^{x + y}) = z e^{x + y}

\frac{\partial}{\partial x} (x y) = y

= z e^{x + y} - y

\frac{d}{d x} ((x + 1) (x + 1 - \frac{1}{x + 2}))

\int_{0}^{π} 3 sin^{4} (3 t) d t

in v erse l a pl a ce \frac{15}{( s + 10 ) ( s + 11 )}

\int_{0}^{2.8} 0.2 x d x

d er i v a t i v e \frac{4 π r ^{3}}{3}