What is the tangent of f(x)=12sqrt(x),(1,12) ?

The tangent of f(x)=12sqrt(x),(1,12) is y=6x+6

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tangent of f(x)=12sqrt(x),(1,12)

tangent of

f (x) = 12 x, (1, 12)

y = 6 x + 6

Solution steps

Find the slope of

f (x) = 12 x : \frac{df ( x )}{d x} = \frac{6}{x}

Compute the slope of

f (x) = 12 x

(1, 12) : m = 6

Find the line with slope m=

6

and passing through

(1, 12) : y = 6 x + 6

y = 6 x + 6

\int sec^{11} (x) d x

x^{\frac{6}{5}} + e^{- 3 x}

\int \frac{1}{x ^{2} + 3 x + 2} d x

x \to 2 lim (\frac{x ^{2} - 1}{x - 2})

\int 4 sin^{4} (x co) s^{2} x d x

What is the tangent of f(x)=12sqrt(x),(1,12) ?
The tangent of f(x)=12sqrt(x),(1,12) is y=6x+6