(\partial)/(\partial x)(ln(x+6y+9z))

Lösung

\frac{\partial}{\partial x} (ln (x + 6 y + 9 z))

\frac{1}{x + 6 y + 9 z}

Schritte zur Lösung

\frac{\partial}{\partial x} (ln (x + 6 y + 9 z))

Behandle

y, z

als Konstanten

Wende die Kettenregel an:

\frac{1}{x + 6 y + 9 z} \frac{\partial}{\partial x} (x + 6 y + 9 z)

= \frac{1}{x + 6 y + 9 z} \frac{\partial}{\partial x} (x + 6 y + 9 z)

\frac{\partial}{\partial x} (x + 6 y + 9 z) = 1

= \frac{1}{x + 6 y + 9 z} \cdot 1

Vereinfache

= \frac{1}{x + 6 y + 9 z}

\int_{0}^{\frac{π}{2}} tan (\frac{x}{2}) d x

25 y^{^{''}} - 40 y^{^{'}} + 16 y = 0, y (0) = 4, y^{^{'}} (0) = - 5

\int ln (x^{\frac{1}{2}}) d x

\frac{\partial}{\partial x} (e^{e^{x}})

\frac{d}{d θ} (sin (θ) + cos (θ))