inverselaplace 1/((s-3)^3)

Lösung

inverse laplace transformation

\frac{1}{( s - 3 ) ^{3}}

\frac{e ^{3 t} t ^{2}}{2}

Schritte zur Lösung

L^{- 1} {\frac{1}{( s - 3 ) ^{3}}}

Wende inverse Transformationsregel an: if

L^{- 1} {F (s)} = f (t)

dann

L^{- 1} {F (s - a)} = e^{a t} f (t)

Für

\frac{1}{( s - 3 ) ^{3}} : a = 3, F (s) = \frac{1}{s ^{3}}

= e^{3 t} L^{- 1} {\frac{1}{s ^{3}}}

L^{- 1} {\frac{1}{s ^{3}}} : \frac{t ^{2}}{2}

= \frac{e ^{3 t} t ^{2}}{2}

\frac{d v}{d t} = - k t v^{2}

d er i v a t i v e f (x) = 15 x ln (8 x)

\frac{\partial}{\partial x} (- 6 + 5 - 6 x)

\frac{d}{d x} (\frac{2}{x + 3})

n = 0 \sum \infty r^{n}