integral of (x^{20}-5x^4)^6(x^{19}-x^3)

Lösung

\int (x^{20} - 5 x^{4})^{6} (x^{19} - x^{3}) d x

\frac{x ^{140}}{140} - \frac{x ^{124}}{4} + \frac{15 x ^{108}}{4} - \frac{125 x ^{92}}{4} + \frac{625 x ^{76}}{4} - \frac{1875 x ^{60}}{4} + \frac{3125 x ^{44}}{4} - \frac{15625 x ^{28}}{28} + C

Schritte zur Lösung

\int (x^{20} - 5 x^{4})^{6} (x^{19} - x^{3}) d x

Multipliziere aus

(x^{20} - 5 x^{4})^{6} (x^{19} - x^{3}) : x^{139} - 31 x^{123} + 405 x^{107} - 2875 x^{91} + 11875 x^{75} - 28125 x^{59} + 34375 x^{43} - 15625 x^{27}

= \int x^{139} - 31 x^{123} + 405 x^{107} - 2875 x^{91} + 11875 x^{75} - 28125 x^{59} + 34375 x^{43} - 15625 x^{27} d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int x^{139} d x - \int 31 x^{123} d x + \int 405 x^{107} d x - \int 2875 x^{91} d x + \int 11875 x^{75} d x - \int 28125 x^{59} d x + \int 34375 x^{43} d x - \int 15625 x^{27} d x

\int x^{139} d x = \frac{x ^{140}}{140}

\int 31 x^{123} d x = \frac{x ^{124}}{4}

\int 405 x^{107} d x = \frac{15 x ^{108}}{4}

\int 2875 x^{91} d x = \frac{125 x ^{92}}{4}

\int 11875 x^{75} d x = \frac{625 x ^{76}}{4}

\int 28125 x^{59} d x = \frac{1875 x ^{60}}{4}

\int 34375 x^{43} d x = \frac{3125 x ^{44}}{4}

\int 15625 x^{27} d x = \frac{15625 x ^{28}}{28}

= \frac{x ^{140}}{140} - \frac{x ^{124}}{4} + \frac{15 x ^{108}}{4} - \frac{125 x ^{92}}{4} + \frac{625 x ^{76}}{4} - \frac{1875 x ^{60}}{4} + \frac{3125 x ^{44}}{4} - \frac{15625 x ^{28}}{28}

Füge eine Konstante zur Lösung hinzu

= \frac{x ^{140}}{140} - \frac{x ^{124}}{4} + \frac{15 x ^{108}}{4} - \frac{125 x ^{92}}{4} + \frac{625 x ^{76}}{4} - \frac{1875 x ^{60}}{4} + \frac{3125 x ^{44}}{4} - \frac{15625 x ^{28}}{28} + C

\int \frac{( x ^{2} + 1 )}{( x + 1 ) ^{2}} e^{x} d x

t an g e n t f (x) = x^{2} + 5 x - 3, at x = - 3

\frac{\partial}{\partial y} (e^{1 + x^{2} - y^{2}})

\frac{d}{d x} (\frac{3}{x ^{4} + 2})

t an g e n t f (x) = x^{2} - \frac{1}{x}, (2, 3.5)