integral from 1 to 2 of xln(8x)

Lösung

\int_{1}^{2} x ln (8 x) d x

- \frac{3}{4} + \frac{13}{2} ln (2)

Dezimale

3.75545 \dots

Schritte zur Lösung

\int_{1}^{2} x ln (8 x) d x

Wende die partielle Integration an

= [\frac{1}{2} x^{2} ln (8 x) - \int \frac{x}{2} d x]_{1}^{2}

\int \frac{x}{2} d x = \frac{x ^{2}}{4}

= [\frac{1}{2} x^{2} ln (8 x) - \frac{x ^{2}}{4}]_{1}^{2}

Berechne die Grenzen:

- \frac{3}{4} + \frac{13}{2} ln (2)

= - \frac{3}{4} + \frac{13}{2} ln (2)

\int \frac{x ^{2} + 1}{( x - 5 ) ( x - 4 ) ^{2}} d x

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