(dy)/(dx)=-((2x^2+y))/((x^2y-x))

Lösung

\frac{d y}{d x} = - \frac{( 2 x ^{2} + y )}{( x ^{2} y - x )}

y = \frac{1 + - 2 x ^{2} ( 2 x - c _{1} ) + 1}{x}, y = \frac{1 - - 2 x ^{2} ( 2 x - c _{1} ) + 1}{x}

Schritte zur Lösung

\frac{d y}{d x} = - \frac{( 2 x ^{2} + y )}{( x ^{2} y - x )}

Solve exact ODE:

y = \frac{1 + - 2 x ^{2} ( 2 x - c _{1} ) + 1}{x}, y = \frac{1 - - 2 x ^{2} ( 2 x - c _{1} ) + 1}{x}

y = \frac{1 + - 2 x ^{2} ( 2 x - c _{1} ) + 1}{x}, y = \frac{1 - - 2 x ^{2} ( 2 x - c _{1} ) + 1}{x}

\frac{\partial}{\partial x} (e^{t} cos (x))

d er i v a t i v e 7 x^{3} + 5 x^{2} + 4 x

\frac{\partial}{\partial x} (cos (x + 6 y))

\int \frac{2 x ^{3} - 3 x ^{2} + 1}{x ^{2}} d x

\frac{d}{d t} (cos^{2} (t))