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tangent y=3x^2+2^2x^2+1,(-1,0)

解答

切线

y = 3 x^{2} + 2^{2} x^{2} + 1, (- 1, 0)

解答

y = (414 - 14) x + 414 - 14 or y = (- 414 - 14) x - 14 - 414

求解步骤

y = 3 x^{2} + 2^{2} x^{2} + 1 : y = 7 x^{2} + 1

(- 1, 0)

处的切线斜率:

m = \frac{7 x ^{2} + 1}{x + 1}

计算

y = 7 x^{2} + 1

的斜率:

m = 14 x

解

14 x = \frac{7 x ^{2} + 1}{x + 1} : x = \frac{- 7 + 2 14}{7}, x = - \frac{7 + 2 14}{7}

求出

x = \frac{- 7 + 2 14}{7}

处的切线:

y = (414 - 14) x + 414 - 14

求出

x = - \frac{7 + 2 14}{7}

处的切线:

y = (- 414 - 14) x - 14 - 414

y = (414 - 14) x + 414 - 14 or y = (- 414 - 14) x - 14 - 414

作图

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