What is the derivative of x^2+e^{x^2} ?

The derivative of x^2+e^{x^2} is 2x+e^{x^2}*2x

What is the first derivative of x^2+e^{x^2} ?

The first derivative of x^2+e^{x^2} is 2x+e^{x^2}*2x

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\frac{d}{d x} (x^{2} + e^{x^{2}})

2 x + e^{x^{2}} \cdot 2 x

Solution steps

\frac{d}{d x} (x^{2} + e^{x^{2}})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) + \frac{d}{d x} (e^{x^{2}})

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (e^{x^{2}}) = e^{x^{2}} \cdot 2 x

= 2 x + e^{x^{2}} \cdot 2 x

\int sin^{3} (x) cos^{10} (x) d x

\frac{d}{d x} (\frac{2}{5} x^{\frac{5}{2}})

\int (x^{3} - 2 x^{\frac{1}{2}} + 4)^{2} d x

\frac{d}{d x} (\frac{1}{y - 5 x ^{2}})

y^{^{'}} - y = 2 t

What is the derivative of x^2+e^{x^2} ?
The derivative of x^2+e^{x^2} is 2x+e^{x^2}*2x
What is the first derivative of x^2+e^{x^2} ?
The first derivative of x^2+e^{x^2} is 2x+e^{x^2}*2x