integral from 0 to 2 of x^2-2x

解答

\int_{0}^{2} x^{2} - 2 x d x

- \frac{4}{3}

十进制

- 1.33333 \dots

求解步骤

\int_{0}^{2} x^{2} - 2 x d x

使用积分加法定则:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{2} x^{2} d x - \int_{0}^{2} 2 x d x

\int_{0}^{2} x^{2} d x = \frac{8}{3}

\int_{0}^{2} 2 x d x = 4

= \frac{8}{3} - 4

化简

\frac{8}{3} - 4 : - \frac{4}{3}

= - \frac{4}{3}

in v erse l a pl a ce \frac{1}{( s - 4 ) ( s - 5 )}

\frac{\partial}{\partial x} (9 y)

\frac{d}{d x} (b x^{2})

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d er i v a t i v e y = (2 x - 2)^{4} (x^{2} + x + 1)^{5}