What is the solution for (dy)/(dx)(1+e^x)=e^{x-y} ?

The solution for (dy)/(dx)(1+e^x)=e^{x-y} is y=ln(ln(1+e^x)+c_{1})

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(dy)/(dx)(1+e^x)=e^{x-y}

\frac{d y}{d x} (1 + e^{x}) = e^{x - y}

y = ln (ln (1 + e^{x}) + c_{1})

Solution steps

\frac{d y}{d x} (1 + e^{x}) = e^{x - y}

Solve separable ODE:

y = ln (ln (1 + e^{x}) + c_{1})

y = ln (ln (1 + e^{x}) + c_{1})

f (x) = e^{x}, at x = ln (2)

\frac{\partial}{\partial x} (2 x - y e^{y})

in (2 x), (0, 2)

\frac{d y}{d x} = 3 (1 + y) (1 - x)

\int \frac{1}{x 36 x ^{2} - 36} d x

What is the solution for (dy)/(dx)(1+e^x)=e^{x-y} ?
The solution for (dy)/(dx)(1+e^x)=e^{x-y} is y=ln(ln(1+e^x)+c_{1})