What is laplacetransform \delta(t-1) ?

The answer to laplacetransform \delta(t-1) is e^{-s}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

laplacetransform \delta(t-1)

laplace transform

δ (t - 1)

e^{- s}

Solution steps

L {δ (t - 1)}

Use Laplace Transform table:

L {δ (t - c)} = e^{- cs}, c > 0

L {δ (t - 1)} = e^{- 1 \cdot s}

= e^{- 1 \cdot s}

= e^{- s}

\int_{0}^{π} cos (x + π) d x

\int \frac{x ^{2}}{x} d x

\frac{\partial}{\partial x} (3 a x^{2} + e^{xx} + e^{x})

\int x^{2} - 4 x + 1 d x

\frac{d}{d x} (\frac{5 x - x ^{2}}{x} - 3 cot (x))

What is laplacetransform \delta(t-1) ?
The answer to laplacetransform \delta(t-1) is e^{-s}