xy^'-2y=x^4,y(1)=0

Lösung

x y^{^{'}} - 2 y = x^{4}, y (1) = 0

y = \frac{x ^{4}}{2} - \frac{x ^{2}}{2}

Schritte zur Lösung

x y^{'} (x) - 2 y = x^{4}

Solve linear ODE:

y = \frac{x ^{4}}{2} - \frac{x ^{2}}{2}

y = \frac{x ^{4}}{2} - \frac{x ^{2}}{2}

x \to 9 lim (3 x - 9)

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