derivative (2x^2+1)/x

Lösung

ableitung von

\frac{2 x ^{2} + 1}{x}

\frac{2 x ^{2} - 1}{x ^{2}}

Schritte zur Lösung

\frac{d}{d x} (\frac{2 x ^{2} + 1}{x})

Wende die Quotientenregel an:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( 2 x ^{2} + 1 ) x - \frac{d x}{d x} ( 2 x ^{2} + 1 )}{x ^{2}}

\frac{d}{d x} (2 x^{2} + 1) = 4 x

\frac{d x}{d x} = 1

= \frac{4 xx - 1 \cdot ( 2 x ^{2} + 1 )}{x ^{2}}

Vereinfache

\frac{4 xx - 1 \cdot ( 2 x ^{2} + 1 )}{x ^{2}} : \frac{2 x ^{2} - 1}{x ^{2}}

= \frac{2 x ^{2} - 1}{x ^{2}}

\frac{d}{d x} (\frac{25 - x ^{2}}{32 x})

\int_{- 1}^{1} x^{2} e^{x^{3} + 1} d x

\frac{d}{d x} (4 x^{5} - \frac{3}{x ^{2}})

\frac{d}{d x} (e^{4 x^{2}} \cdot 8 x)

d er i v a t i v e f (x) = x^{3} - 15 x