implicit (dy)/(dx),y=arccos(4x^2)

解答

隐函数求导

\frac{d y}{d x}, y = arccos (4 x^{2})

\frac{d y}{d x} = - \frac{8 x}{1 - 16 x ^{4}}

求解步骤

y = arccos (4 x^{2})

将

y

视为

y (x)

对两侧微分:

\frac{d y}{d x} = - \frac{8 x}{1 - 16 x ^{4}}

整理

\frac{d y}{d x} : \frac{d y}{d x} = - \frac{8 x}{1 - 16 x ^{4}}

\frac{d y}{d x} = - \frac{8 x}{1 - 16 x ^{4}}

\int 3 sin (2 x) cos (3 x) d x

\int_{0}^{4} ((4 - x) x) d x

\frac{d y}{d x} = e^{4 x} - 3 y

x \to \infty lim (x^{2} y^{2})

d er i v a t i v e f (x) = \frac{3 x - 9}{2 x + 8}