y^{''}+1=0

解答

y^{^{''}} + 1 = 0

y = - \frac{t ^{2}}{2} + c_{1} t + c_{2}

求解步骤

y^{''} (t) + 1 = 0

整理

y^{''} (t) : y^{''} (t) = - 1

解

y^{''} (t) = - 1 : y^{'} (t) = - t + c_{1}

解

y^{'} (t) = - t + c_{1} : y = - \frac{t ^{2}}{2} + c_{1} t + c_{2}

y = - \frac{t ^{2}}{2} + c_{1} t + c_{2}

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