en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular Calculus >

area y=(|x-2|)^3,y=8-4x

Solution

area

y = (∣ x - 2 ∣)^{3}, y = 8 - 4 x

Solution

4

Solution steps

Apply the area formula:

\int_{0}^{2} ∣ x - 2 ∣^{3} - (8 - 4 x) d x

Solve

\int_{0}^{2} ∣ x - 2 ∣^{3} - (8 - 4 x) d x : 4

The area is:

= 4

Graph

Popular Examples

limit as x approaches 0 of ((2^x-1))/x

x \to 0 lim (\frac{( 2 ^{x} - 1 )}{x})

integral of 1/(y^2-y^3)

\int \frac{1}{y ^{2} - y ^{3}} d y

integral of x^3((2x^2+1)/x)

\int x^{3} (\frac{2 x ^{2} + 1}{x}) d x

derivative of x/(x+3)

d er i v a t i v e \frac{x}{x + 3}

integral from 0 to 2 of 5^{-x}

\int_{0}^{2} 5^{- x} d x

Frequently Asked Questions (FAQ)

What is area y=(|x-2|)^3,y=8-4x ?
The answer to area y=(|x-2|)^3,y=8-4x is 4