What is the derivative of sin(3x^3) ?

The derivative of sin(3x^3) is cos(3x^3)*9x^2

What is the first derivative of sin(3x^3) ?

The first derivative of sin(3x^3) is cos(3x^3)*9x^2

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\frac{d}{d x} (sin (3 x^{3}))

cos (3 x^{3}) \cdot 9 x^{2}

Solution steps

\frac{d}{d x} (sin (3 x^{3}))

Apply the chain rule:

cos (3 x^{3}) \frac{d}{d x} (3 x^{3})

= cos (3 x^{3}) \frac{d}{d x} (3 x^{3})

\frac{d}{d x} (3 x^{3}) = 9 x^{2}

= cos (3 x^{3}) \cdot 9 x^{2}

\int \frac{2 x - 13}{x ^{2} - 13 x + 50} d x

y^{^{'}} + 0.564 y^{2} = 0

\frac{\partial}{\partial x} (4 x z sin (y))

n = 2 \sum \infty \frac{6}{n ^{2} - 1}

\frac{\partial}{\partial y} (cos (x y) + sin (yz))

What is the derivative of sin(3x^3) ?
The derivative of sin(3x^3) is cos(3x^3)*9x^2
What is the first derivative of sin(3x^3) ?
The first derivative of sin(3x^3) is cos(3x^3)*9x^2