What is the derivative of f(x)=ln(x+6) ?

The derivative of f(x)=ln(x+6) is 1/(x+6)

What is the first derivative of f(x)=ln(x+6) ?

The first derivative of f(x)=ln(x+6) is 1/(x+6)

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derivative of

f (x) = ln (x + 6)

\frac{1}{x + 6}

Solution steps

\frac{d}{d x} (ln (x + 6))

Apply the chain rule:

\frac{1}{x + 6} \frac{d}{d x} (x + 6)

= \frac{1}{x + 6} \frac{d}{d x} (x + 6)

\frac{d}{d x} (x + 6) = 1

= \frac{1}{x + 6} \cdot 1

Simplify

= \frac{1}{x + 6}

\int_{0}^{15} 1000 e^{- 0.05 t} d t

x \to 1 lim (3 - 3 x)

y^{^{'}} + \frac{1}{6} y = 40

\frac{\partial}{\partial y} ((x + y + z)^{2})

\int e^{- x} - e^{- 3 x} d x

What is the derivative of f(x)=ln(x+6) ?
The derivative of f(x)=ln(x+6) is 1/(x+6)
What is the first derivative of f(x)=ln(x+6) ?
The first derivative of f(x)=ln(x+6) is 1/(x+6)