What is laplacetransform sin(t+pi) ?

The answer to laplacetransform sin(t+pi) is -1/(s^2+1)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

laplacetransform sin(t+pi)

laplace transform

sin (t + π)

- \frac{1}{s ^{2} + 1}

Solution steps

L {sin (t + π)}

Use Laplace Transform table:

L {sin (a t + b)} = \frac{s \cdot sin ( b ) + a \cdot cos ( b )}{s ^{2} + a ^{2}}

L {sin (t + π)} = \frac{s sin ( π ) + 1 \cdot cos ( π )}{s ^{2} + 1 ^{2}}

= \frac{s sin ( π ) + 1 \cdot cos ( π )}{s ^{2} + 1 ^{2}}

= - \frac{1}{s ^{2} + 1}

\int \frac{1}{( x - 1 ) ^{2} ( x - 2 )} d x

y = 9 e^{x} cos (x)

1 - x

\int \frac{1}{m ^{3} + m} d m

\frac{d}{d x} (e^{- 6 x} - 6 e^{- 6 x} x)

What is laplacetransform sin(t+pi) ?
The answer to laplacetransform sin(t+pi) is -1/(s^2+1)