integral from 1 to infinity of 1/(x^2+3)

Lösung

\int_{1}^{\infty} \frac{1}{x ^{2} + 3} d x

\frac{π}{3 3}

Dezimale

0.60459 \dots

Schritte zur Lösung

\int_{1}^{\infty} \frac{1}{x ^{2} + 3} d x

Berechne das unbestimmte Integral:

\int \frac{1}{x ^{2} + 3} d x = \frac{1}{3} arctan (\frac{x}{3}) + C

Berechne die Grenzen:

\int_{1}^{\infty} \frac{1}{x ^{2} + 3} d x = \frac{π}{2 3} - \frac{π}{6 3}

= \frac{π}{2 3} - \frac{π}{6 3}

Vereinfache

= \frac{π}{3 3}

d er i v a t i v e y = 3 1.6 x^{2} + 4.9

d er i v a t i v e f (t) = \frac{1}{2} (9 t^{2} + t)^{- 3}

x \to \infty lim (2 1^{x})

\frac{\partial}{\partial y} (cos (12 x) sin (2 y))

d er i v a t i v e f (x) = - 247