limit as x approaches 1/3 of (x+3)/(x+4)

解答

x \to \frac{1}{3} lim (\frac{x + 3}{x + 4})

\frac{10}{13}

十进制

0.76923 \dots

求解步骤

x \to \frac{1}{3} lim (\frac{x + 3}{x + 4})

代入值

x = \frac{1}{3}

= \frac{\frac{1}{3} + 3}{\frac{1}{3} + 4}

化简

\frac{\frac{1}{3} + 3}{\frac{1}{3} + 4} : \frac{10}{13}

= \frac{10}{13}

\frac{d}{d x} ((x^{2}) d x)

x \to - 3 lim (\frac{x ^{2} + x}{x + 3})

\int 3 y^{3} e^{x y} d x

\int x^{2} e^{2 x + 1} d x

t an g e n t f (x) = - 3 x^{2} - 5, at x = 0