integral from 1 to 4 of f(x)

解答

\int_{1}^{4} f (x) d x

\frac{15 f}{2}

求解步骤

\int_{1}^{4} f x d x

提出常数:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= f \cdot \int_{1}^{4} x d x

使用幂法则

= f [\frac{x ^{2}}{2}]_{1}^{4}

带入上下限计算后得:

\frac{15}{2}

= f \frac{15}{2}

化简

= \frac{15 f}{2}

\frac{d}{d x} (x (x^{5} + 1)^{3})

\frac{\partial}{\partial y} (x e^{y} - ln (x))

d er i v a t i v e - x - \frac{1}{x}

x \to 0 lim (x^{- 1})

\int_{- 2}^{3} \frac{14}{x ^{4}} d x