y^{''}+400y=sec(20x)

Lösung

y^{^{''}} + 400 y = sec (20 x)

y = c_{1} cos (20 x) + c_{2} sin (20 x) + \frac{1}{400} ln (cos (20 x)) cos (20 x) + \frac{1}{20} x sin (20 x)

Schritte zur Lösung

y^{''} (x) + 400 y = sec (20 x)

Solve linear ODE:

y = c_{1} cos (20 x) + c_{2} sin (20 x) + \frac{1}{400} ln (cos (20 x)) cos (20 x) + \frac{1}{20} x sin (20 x)

y = c_{1} cos (20 x) + c_{2} sin (20 x) + \frac{1}{400} ln (cos (20 x)) cos (20 x) + \frac{1}{20} x sin (20 x)

x \to - 3 + lim (4 x^{2} - 7)

\int e^{2 x} (x^{2} + 2 x) d x

d er i v a t i v e (t + 4)^{(\frac{2}{3})} (2 t^{2} - 4)^{3}

x \to 2 lim (x^{2} + 12)

\frac{d ^{2}}{d x ^{2}} (\frac{7}{8 x ^{6}})