What is the limit as x approaches 0 of (x^2-1)/(x+1) ?

The limit as x approaches 0 of (x^2-1)/(x+1) is -1

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limit as x approaches 0 of (x^2-1)/(x+1)

x \to 0 lim (\frac{x ^{2} - 1}{x + 1})

- 1

Solution steps

x \to 0 lim (\frac{x ^{2} - 1}{x + 1})

Plug in the value

x = 0

= \frac{0 ^{2} - 1}{0 + 1}

Simplify

\frac{0 ^{2} - 1}{0 + 1} : - 1

= - 1

\int \frac{8}{3 cos ( 2 x ) + 1} d x

x \to 2 + lim (\frac{1}{x ^{2} - 4})

\int \frac{ln ( sin ( x ) )}{tan ( x )} d x

\frac{x}{9} - \frac{9}{x}

f (x) = e^{c o s (x)}

What is the limit as x approaches 0 of (x^2-1)/(x+1) ?
The limit as x approaches 0 of (x^2-1)/(x+1) is -1