What is the tangent of y=-5-6x^2,(-4,-101) ?

The tangent of y=-5-6x^2,(-4,-101) is y=48x+91

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tangent of y=-5-6x^2,(-4,-101)

tangent of

y = - 5 - 6 x^{2}, (- 4, - 101)

y = 48 x + 91

Solution steps

Find the slope of

y = - 5 - 6 x^{2} : \frac{d y}{d x} = - 12 x

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 48

Find the line with slope m=

48

and passing through

(- 4, - 101) : y = 48 x + 91

y = 48 x + 91

d er i v a t i v e p (t) = 5 e^{0.0278 t}

\frac{d}{d x} (\frac{1}{2} x^{2} + 1)

x \to - 3 lim (\frac{x}{x - 4})

\int 2 e^{x} - 1 d x

\int 4 x + 1 d x

What is the tangent of y=-5-6x^2,(-4,-101) ?
The tangent of y=-5-6x^2,(-4,-101) is y=48x+91