y^{''}+y^'=2

Lösung

y^{^{''}} + y^{^{'}} = 2

y = c_{1} + c_{2} e^{- t} + 2 t

Schritte zur Lösung

y^{''} (t) + y^{'} (t) = 2

Solve linear ODE:

y = c_{1} + c_{2} e^{- t} + 2 t

y = c_{1} + c_{2} e^{- t} + 2 t

t an g e n t f (x) = 2 x + 1, at x = 4

\frac{d}{d t} (\frac{y}{t} - (\frac{y}{t})^{2})

\int_{1}^{2} \frac{4}{x} - \frac{16}{x ^{2}} d x

\frac{\partial}{\partial y} (y - e^{- 2 x^{2} y})

\frac{\partial}{\partial x} (x (x - 2 y))