derivative of (2x+1/(x+5))

解答

\frac{d}{d x} (\frac{2 x + 1}{x + 5})

\frac{9}{( x + 5 ) ^{2}}

求解步骤

\frac{d}{d x} (\frac{2 x + 1}{x + 5})

使用微分除法定则:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( 2 x + 1 ) ( x + 5 ) - \frac{d}{d x} ( x + 5 ) ( 2 x + 1 )}{( x + 5 ) ^{2}}

\frac{d}{d x} (2 x + 1) = 2

\frac{d}{d x} (x + 5) = 1

= \frac{2 ( x + 5 ) - 1 \cdot ( 2 x + 1 )}{( x + 5 ) ^{2}}

化简

\frac{2 ( x + 5 ) - 1 \cdot ( 2 x + 1 )}{( x + 5 ) ^{2}} : \frac{9}{( x + 5 ) ^{2}}

= \frac{9}{( x + 5 ) ^{2}}

\int (\frac{7}{x} - \frac{6}{x ^{3}}) d x

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