(tan(3x))^'

Lösung

(tan (3 x))^{^{'}}

sec^{2} (3 x) \cdot 3

Schritte zur Lösung

(tan (3 x))^{'}

Wende die Kettenregel an:

sec^{2} (3 x) (3 x)^{'}

= sec^{2} (3 x) (3 x)^{'}

(3 x)^{'} = 3

= sec^{2} (3 x) \cdot 3

\int_{1}^{2} (1 - x^{2}) - (3 - 3 x) d x

\frac{d x}{d t} = x^{2} - 6 x + 14

d er i v a t i v e f (x) = 2 x^{4} + x^{3} - x^{2} + 4

\int_{0}^{x} 1 + 9 t d t

\int 10 sin (x) - 2 cos (x) d x