(d^4)/(dx^4)(1/(1+x))

Lösung

\frac{d ^{4}}{d x ^{4}} (\frac{1}{1 + x})

\frac{24}{( 1 + x ) ^{5}}

Schritte zur Lösung

\frac{d ^{4}}{d x ^{4}} (\frac{1}{1 + x})

\frac{d}{d x} (\frac{1}{1 + x}) = - \frac{1}{( 1 + x ) ^{2}}

= \frac{d ^{3}}{d x ^{3}} (- \frac{1}{( 1 + x ) ^{2}})

\frac{d}{d x} (- \frac{1}{( 1 + x ) ^{2}}) = \frac{2}{( 1 + x ) ^{3}}

= \frac{d ^{2}}{d x ^{2}} (\frac{2}{( 1 + x ) ^{3}})

\frac{d}{d x} (\frac{2}{( 1 + x ) ^{3}}) = - \frac{6}{( 1 + x ) ^{4}}

= \frac{d}{d x} (- \frac{6}{( 1 + x ) ^{4}})

\frac{d}{d x} (- \frac{6}{( 1 + x ) ^{4}}) = \frac{24}{( 1 + x ) ^{5}}

= \frac{24}{( 1 + x ) ^{5}}

f (x) = \frac{ln ( x ) - 1}{ln ^{2} ( x )}

d er i v a t i v e f (x) = \frac{x ^{2} - 3 x}{x + 1}

y^{^{''}} - y^{^{'}} + y = 0

im pl i c i t \frac{d y}{d x}, x^{8} - y = 0

\int x sin (4 x) d x