What is the derivative of e^{2x}+e^x ?

The derivative of e^{2x}+e^x is e^{2x}*2+e^x

What is the first derivative of e^{2x}+e^x ?

The first derivative of e^{2x}+e^x is e^{2x}*2+e^x

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\frac{d}{d x} (e^{2 x} + e^{x})

e^{2 x} \cdot 2 + e^{x}

Solution steps

\frac{d}{d x} (e^{2 x} + e^{x})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (e^{2 x}) + \frac{d}{d x} (e^{x})

\frac{d}{d x} (e^{2 x}) = e^{2 x} \cdot 2

\frac{d}{d x} (e^{x}) = e^{x}

= e^{2 x} \cdot 2 + e^{x}

\frac{d y}{d t} = - 3 y + 12, y (0) = 6

f (x) = (4 - x^{2}) (x + 1)

\frac{d y}{d x} = \frac{1}{10} (500 y - y^{2})

\frac{d y}{d t} = e^{- y}

\int \frac{1}{9} e^{9 x} d x

What is the derivative of e^{2x}+e^x ?
The derivative of e^{2x}+e^x is e^{2x}*2+e^x
What is the first derivative of e^{2x}+e^x ?
The first derivative of e^{2x}+e^x is e^{2x}*2+e^x