integral from 0 to 3 of x^3-5x

Lösung

\int_{0}^{3} x^{3} - 5 x d x

- \frac{9}{4}

Dezimale

- 2.25

Schritte zur Lösung

\int_{0}^{3} x^{3} - 5 x d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{3} x^{3} d x - \int_{0}^{3} 5 x d x

\int_{0}^{3} x^{3} d x = \frac{81}{4}

\int_{0}^{3} 5 x d x = \frac{45}{2}

= \frac{81}{4} - \frac{45}{2}

Vereinfache

\frac{81}{4} - \frac{45}{2} : - \frac{9}{4}

= - \frac{9}{4}

\frac{d y}{d x} = \frac{1}{7} y cos^{2} (y)

(y sin (x) + x y cos (x)) d x + (x sin (x) + 1) d y = 0

x \to 0 lim (\frac{x}{e ^{x}})

n \to \infty lim (ln (n))

t an g e n t x^{2} + \frac{4}{x} - 10, at x = 8