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Beliebt Rechnen >

2x+y+(x+2y)y^'=0

Lösung

2 x + y + (x + 2 y) y^{^{'}} = 0

Lösung

y = \frac{- x + - 3 x ^{2} + c _{1}}{2}, y = \frac{- x - - 3 x ^{2} + c _{1}}{2}

Schritte zur Lösung

2 x + y + (x + 2 y) y^{'} (x) = 0

Solve exact ODE:

y = \frac{- x + - 3 x ^{2} + c _{1}}{2}, y = \frac{- x - - 3 x ^{2} + c _{1}}{2}

y = \frac{- x + - 3 x ^{2} + c _{1}}{2}, y = \frac{- x - - 3 x ^{2} + c _{1}}{2}

Graph

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