(dy)/(dx)= x/(1+2y)

Lösung

\frac{d y}{d x} = \frac{x}{1 + 2 y}

y = \frac{- 1 + - 2 ( - x ^{2} - c _{1} ) + 1}{2}, y = - \frac{- 2 ( - x ^{2} - c _{1} ) + 1 + 1}{2}

Schritte zur Lösung

\frac{d y}{d x} = \frac{x}{1 + 2 y}

Solve separable ODE:

y = \frac{- 1 + - 2 ( - x ^{2} - c _{1} ) + 1}{2}, y = - \frac{- 2 ( - x ^{2} - c _{1} ) + 1 + 1}{2}

y = \frac{- 1 + - 2 ( - x ^{2} - c _{1} ) + 1}{2}, y = - \frac{- 2 ( - x ^{2} - c _{1} ) + 1 + 1}{2}

t an g e n t f (x) = \frac{x ^{3}}{3} + 2 x^{2} + 13 x - 5

n = 1 \sum \infty \frac{n}{ln ( 2 n )}

t an g e n t x^{3} - 2 x + 2, at x = 3, y = 21

\frac{\partial}{\partial x} (\frac{8 x + 5 y}{z})

\frac{\partial}{\partial x} (2 (\frac{y}{x})^{0.5})