What is the integral of x^{16}e^{x^{17}} ?

The integral of x^{16}e^{x^{17}} is 1/17 e^{x^{17}}+C

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integral of x^{16}e^{x^{17}}

\int x^{16} e^{x^{17}} d x

\frac{1}{17} e^{x^{17}} + C

Solution steps

\int x^{16} e^{x^{17}} d x

Apply u-substitution

: \int \frac{1}{17} d u

= \int \frac{1}{17} d u

Integral of a constant:

\int a d x = a x

= \frac{1}{17} u

Substitute back

u = e^{x^{17}}

= \frac{1}{17} e^{x^{17}}

Add a constant to the solution

= \frac{1}{17} e^{x^{17}} + C

\frac{\partial}{\partial x} (e^{7 x})

x \to 3 - lim (\frac{2}{x + 3})

\frac{d}{d x} (e^{s i n (2 x)})

\int (sin (x) + cos (x)) e^{x} d x

\frac{d}{d x} (e^{x^{3} + 2})

What is the integral of x^{16}e^{x^{17}} ?
The integral of x^{16}e^{x^{17}} is 1/17 e^{x^{17}}+C