y^{''}+y=2+x^2

Lösung

y^{^{''}} + y = 2 + x^{2}

y = c_{1} cos (x) + c_{2} sin (x) + x^{2}

Schritte zur Lösung

y^{''} (x) + y = 2 + x^{2}

Solve linear ODE:

y = c_{1} cos (x) + c_{2} sin (x) + x^{2}

y = c_{1} cos (x) + c_{2} sin (x) + x^{2}

\frac{d}{d x} (6^{4} x^{3} + x^{5} - 180 4 x^{2})

\frac{d}{d x} (\frac{- e ^{- x} x - e ^{- x}}{x ^{2}})

\int_{- 7}^{7} (1 + 49 - x^{2}) d x

\frac{d y}{d x} = \frac{x ^{2} + 2 y ^{2}}{x y}

t an g e n t f (x) = \frac{1}{( x - 5 )}, at x = - 3