What is the integral from 10 to 5 of \sqrt[3]{x} ?

The integral from 10 to 5 of \sqrt[3]{x} is -(15\sqrt[3]{5}}{2^{2/3}}+\frac{15\sqrt[3]{5})/4

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integral from 10 to 5 of \sqrt[3]{x}

\int_{10}^{5} 3 x d x

- \frac{15 3 5}{2 ^{\frac{2}{3}}} + \frac{15 3 5}{4}

Decimal

- 9.74585 \dots

Solution steps

\int_{10}^{5} 3 x d x

\int_{a}^{b} f (x) d x = - \int_{b}^{a} f (x) d x, a < b

= - \int_{5}^{10} 3 x d x

Apply the Power Rule

: [\frac{3}{4} x^{\frac{4}{3}}]_{5}^{10}

= - [\frac{3}{4} x^{\frac{4}{3}}]_{5}^{10}

Compute the boundaries:

\frac{15 3 5}{2 ^{\frac{2}{3}}} - \frac{15 3 5}{4}

= - (\frac{15 3 5}{2 ^{\frac{2}{3}}} - \frac{15 3 5}{4})

Simplify

= - \frac{15 3 5}{2 ^{\frac{2}{3}}} + \frac{15 3 5}{4}

(- 6, 9), (7, - 9)

\frac{\partial}{\partial x} (x ln (x + 2 y + 3 z))

\frac{d}{d x} (\frac{csc ( 3 x )}{x ^{3} + 1})

\int t e^{2 t} d t

\int sin^{4} (3 t) d t

What is the integral from 10 to 5 of \sqrt[3]{x} ?
The integral from 10 to 5 of \sqrt[3]{x} is -(15\sqrt[3]{5}}{2^{2/3}}+\frac{15\sqrt[3]{5})/4