What is the derivative of 4(x^2+y^2) ?

The derivative of 4(x^2+y^2) is 4(2x+2y(dy)/(dx))

What is the first derivative of 4(x^2+y^2) ?

The first derivative of 4(x^2+y^2) is 4(2x+2y(dy)/(dx))

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\frac{d}{d x} (4 (x^{2} + y^{2}))

4 (2 x + 2 y \frac{d y}{d x})

Solution steps

\frac{d}{d x} (4 (x^{2} + y^{2}))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 4 \frac{d}{d x} (x^{2} + y^{2})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= 4 (\frac{d}{d x} (x^{2}) + \frac{d}{d x} (y^{2}))

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (y^{2}) = 2 y \frac{d y}{d x}

= 4 (2 x + 2 y \frac{d y}{d x})

x \to 2 lim (3 x)

y = (2 x + 1)^{3} (3 x + 4)^{- 5}

\int (x - 1)^{2} d x

x^{2} d y = (x^{2} + x y + y^{2}) d x

\int 3 x^{5} d x

What is the derivative of 4(x^2+y^2) ?
The derivative of 4(x^2+y^2) is 4(2x+2y(dy)/(dx))
What is the first derivative of 4(x^2+y^2) ?
The first derivative of 4(x^2+y^2) is 4(2x+2y(dy)/(dx))