What is area y=x^2-4x,y=-x^2+4x ?

The answer to area y=x^2-4x,y=-x^2+4x is 64/3

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area y=x^2-4x,y=-x^2+4x

area

y = x^{2} - 4 x, y = - x^{2} + 4 x

\frac{64}{3}

Decimal

21.33333 \dots

Solution steps

Apply the area formula:

\int_{0}^{4} x^{2} - 4 x - (- x^{2} + 4 x) d x

Solve

\int_{0}^{4} x^{2} - 4 x - (- x^{2} + 4 x) d x : \frac{64}{3}

The area is:

= \frac{64}{3}

\int \frac{3}{x} - 2 x + 18 d x

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\int (sin (θ))^{3} d θ

4 sec (x)