integral of (x^2+6x)

Lösung

\int (x^{2} + 6 x) d x

\frac{x ^{3}}{3} + 3 x^{2} + C

Schritte zur Lösung

\int x^{2} + 6 x d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int x^{2} d x + \int 6 x d x

\int x^{2} d x = \frac{x ^{3}}{3}

\int 6 x d x = 3 x^{2}

= \frac{x ^{3}}{3} + 3 x^{2}

Füge eine Konstante zur Lösung hinzu

= \frac{x ^{3}}{3} + 3 x^{2} + C

ma c l a u r in 7 cos (2 x)

x \to 0 + lim ((1 - ln (x))^{x})

\int_{0}^{a} a^{2} + x^{2} d x

n = 0 \sum \infty \frac{n}{3}

\int_{0}^{\frac{π}{2}} cos^{2} (t) d t