y^{''}+25y=2sec(5t)

Lösung

y^{^{''}} + 25 y = 2 sec (5 t)

y = c_{1} cos (5 t) + c_{2} sin (5 t) + \frac{2}{25} ln (cos (5 t)) cos (5 t) + \frac{2}{5} t sin (5 t)

Schritte zur Lösung

y^{''} (t) + 25 y = 2 sec (5 t)

Solve linear ODE:

y = c_{1} cos (5 t) + c_{2} sin (5 t) + \frac{2}{25} ln (cos (5 t)) cos (5 t) + \frac{2}{5} t sin (5 t)

y = c_{1} cos (5 t) + c_{2} sin (5 t) + \frac{2}{25} ln (cos (5 t)) cos (5 t) + \frac{2}{5} t sin (5 t)

x \to 0 lim (5^{x})

n = 6 \sum \infty e^{3 - 4 n}

x \to \infty lim (4 x - x^{2})

\frac{\partial}{\partial y} (x^{\frac{3}{2}} - 3 y)

(x - y arctan (\frac{y}{x})) d x + x arctan (\frac{y}{x}) d y = 0