y^{''}+y=2csc^2(t)

Lösung

y^{^{''}} + y = 2 csc^{2} (t)

y = c_{1} cos (t) + c_{2} sin (t) - 2 cos (t) ln (tan (\frac{t}{2})) - 2

Schritte zur Lösung

y^{''} (t) + y = 2 csc^{2} (t)

Solve linear ODE:

y = c_{1} cos (t) + c_{2} sin (t) - 2 cos (t) ln (tan (\frac{t}{2})) - 2

y = c_{1} cos (t) + c_{2} sin (t) - 2 cos (t) ln (tan (\frac{t}{2})) - 2

\int_{0}^{c} 4 e^{2 x} d x

\int_{0}^{1} (e^{x} - x e^{x^{2}}) d x

\int \frac{v}{1 - v} d v

\int - x + 3 (cos (\frac{n \cdot π \cdot x}{8})) d x

\frac{d}{d x} (\frac{1}{x y})