de

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Beliebt Rechnen >

inverselaplace 2/(5(s+3)^2+125)

Lösung

inverse laplace transformation

\frac{2}{5 ( s + 3 ) ^{2} + 125}

Lösung

e^{- 3 t} \frac{2}{25} sin (5 t)

Schritte zur Lösung

L^{- 1} {\frac{2}{5 ( s + 3 ) ^{2} + 125}}

Wende inverse Transformationsregel an: if

L^{- 1} {F (s)} = f (t)

dann

L^{- 1} {F (s - a)} = e^{a t} f (t)

Für

\frac{2}{5 ( s + 3 ) ^{2} + 125} : a = - 3, F (s) = \frac{2}{5 s ^{2} + 125}

= e^{- 3 t} L^{- 1} {\frac{2}{5 s ^{2} + 125}}

L^{- 1} {\frac{2}{5 s ^{2} + 125}} : \frac{2}{25} sin (5 t)

= e^{- 3 t} \frac{2}{25} sin (5 t)

Beliebte Beispiele

derivative of (x^2/(sqrt(x^3+1)))

\frac{d}{d x} (\frac{x ^{2}}{x ^{3} + 1})

f (x) = 4 sin (4 x)

derivative of ln(3+x^2)

\frac{d}{d x} (ln (3 + x^{2}))

x^{^{'}} + 6 x = 0

sum from n=0 to infinity of 3*(-2/5)^n

n = 0 \sum \infty 3 \cdot (- \frac{2}{5})^{n}