integral from 0 to 5 of x

Lösung

\int_{0}^{5} x d x

\frac{25}{2}

Dezimale

12.5

Schritte zur Lösung

\int_{0}^{5} x d x

Wende die Potenzregel an

= [\frac{x ^{2}}{2}]_{0}^{5}

Berechne die Grenzen:

\frac{25}{2}

= \frac{25}{2}

\int \frac{1}{x ^{2} 10 x + 1} d x

\int e^{θ} sin (θ) d θ

n = 1 \sum \infty \frac{( ( - 3 ) ^{n - 1} )}{5 ^{n}}

\int 2 sin^{3} (x) d x

x \to \infty lim (x a)