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人気のある微分積分 >

derivative f(x)=ax^2+bx

解

導関数

f (x) = a x^{2} + b x

解

2 a x + b

解答ステップ

\frac{d}{d x} (a x^{2} + b x)

和/差の法則を適用:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (a x^{2}) + \frac{d}{d x} (b x)

\frac{d}{d x} (a x^{2}) = 2 a x

\frac{d}{d x} (b x) = b

= 2 a x + b

グラフ

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