taylor x^3-2x^2+3x+5(2)

Lösung

taylor

x^{3} - 2 x^{2} + 3 x + 5 (2)

10 + 3 x - 2 x^{2} + x^{3}

Schritte zur Lösung

Apply the Taylor Formula

= 10 + \frac{\frac{d}{d x} ( x ^{3} - 2 x ^{2} + 3 x + 5 \cdot 2 ) ( 0 )}{1 !} x + \frac{\frac{d ^{2}}{d x ^{2}} ( x ^{3} - 2 x ^{2} + 3 x + 5 \cdot 2 ) ( 0 )}{2 !} x^{2} + \frac{\frac{d ^{3}}{d x ^{3}} ( x ^{3} - 2 x ^{2} + 3 x + 5 \cdot 2 ) ( 0 )}{3 !} x^{3} + \dots

Evaluate Derivatives

= 10 + \frac{3}{1 !} x + \frac{- 4}{2 !} x^{2} + \frac{6}{3 !} x^{3} + \frac{0}{4 !} x^{4} + \frac{0}{5 !} x^{5} + \frac{0}{6 !} x^{6} + \frac{0}{7 !} x^{7} + \frac{0}{8 !} x^{8} + \frac{0}{9 !} x^{9} + \frac{0}{10 !} x^{10}

Fasse zusammen

= 10 + 3 x - 2 x^{2} + x^{3}

\int_{e^{2}}^{e^{5}} (\frac{1}{x}) d x

s l o p e in t erce pt (2, 5), (0, - 9)

d er i v a t i v e \frac{u}{u ^{2} + 5}

\int e^{(- 0.1 x)} d x

\frac{d}{d x} (x^{2} - x + 5)