y^{''}+16y=0

Lösung

y^{^{''}} + 16 y = 0

y = c_{1} cos (4 t) + c_{2} sin (4 t)

Schritte zur Lösung

y^{''} (t) + 16 y = 0

Solve linear ODE:

y = c_{1} cos (4 t) + c_{2} sin (4 t)

y = c_{1} cos (4 t) + c_{2} sin (4 t)

\frac{d}{d x} (\frac{0.25}{5 x ^{2}})

\frac{\partial}{\partial x} ((x^{\frac{1}{2}} + y^{\frac{1}{2}})^{2})

\int 5 + \frac{3 x ^{2}}{2 x ^{3} + 7} d x

\int 300 t e^{\frac{- t ^{2}}{7}} d t

x \to 0 lim (\frac{cos ( 5 x )}{x})