What is the derivative of (x^2+4^2) ?

The derivative of (x^2+4^2) is 4x(x^2+4)

What is the first derivative of (x^2+4^2) ?

The first derivative of (x^2+4^2) is 4x(x^2+4)

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\frac{d}{d x} ((x^{2} + 4)^{2})

4 x (x^{2} + 4)

Solution steps

\frac{d}{d x} ((x^{2} + 4)^{2})

Apply the chain rule:

2 (x^{2} + 4) \frac{d}{d x} (x^{2} + 4)

= 2 (x^{2} + 4) \frac{d}{d x} (x^{2} + 4)

\frac{d}{d x} (x^{2} + 4) = 2 x

= 2 (x^{2} + 4) \cdot 2 x

Simplify

= 4 x (x^{2} + 4)

d er i v a t i v e x e^{x} + e^{x}

\frac{d y}{d x} = \frac{- x ^{2} y}{1 + x ^{3}}

\frac{d}{d t} (1 + (t - y)^{2})

x \to 6 lim (\frac{x ^{2} - 3}{x - 6})

\frac{\partial}{\partial x} (\frac{2}{x - 3})

What is the derivative of (x^2+4^2) ?
The derivative of (x^2+4^2) is 4x(x^2+4)
What is the first derivative of (x^2+4^2) ?
The first derivative of (x^2+4^2) is 4x(x^2+4)