y^{''}+y=0

Lösung

y^{^{''}} + y = 0

y = c_{1} cos (t) + c_{2} sin (t)

Schritte zur Lösung

y^{''} (t) + y = 0

Solve linear ODE:

y = c_{1} cos (t) + c_{2} sin (t)

y = c_{1} cos (t) + c_{2} sin (t)

y^{^{'}} = 2 e^{2 x - y}

\int x ln (x - 1) d x

d er i v a t i v e \frac{x ^{2}}{5 + 8 x}

d er i v a t i v e f (x) = (x^{5} - x^{3} + 3)

\int \frac{1}{x ( 5 + 3 ln ( x ) )} d x